The Success Factors of Standard Chartered Hong Kong Marathon

Presented to

The Department of Business Administration

2011-12

EXECUTIVE SUMMARY

This repost is studying the success factors of Standard Chartered Hong Kong Marathon.

It will be collect the information and data from questionnaire survey and focus groups. Also, it will be through Value Important Performance Grid tool and SWOT analysis that more understand the performance and state of this marathon, then make some recommendation.

ACKNOWLEDGEMENT

This thesis would not have been possible unless someone who give the information support. It is an honor for our group to interview Mrs. Vivian So, the Executive director of HKAAA, and Mr. Wong Ka Man, an committee
It can help us to find out more Standard Chartered Hong Kong Marathon information, such how can prepare for the event.

Moreover, we had used internet to find more secondary information. For example, using Google to research information related to Standard Chartered Hong Kong Marathon. It can easy to research some useful information in the Standard Chartered Hong Kong Marathon, such as, past history and year the participant situation etc. Also, we used Wise News to find some past news.

Primary research
First of all, we have interview with Miss Vivian, the Executive Director of the Hong Kong Amateur Athletic Association (HKAAA) to get more information of Standard Chartered Hong Kong Marathon. So, we can have more information about this event, such as the process of marathon, brand building etc.

Furthermore, we had set questionnaires and used to interview with stakeholders such as, runner and supporter, to find out how they feel about Standard Chartered Hong Kong Marathon. We had interviewed them the days near the marathon. We had finished 384 interviews in different place, such as, sport ground, a competition area etc. Then, it can help us to understand the customer’s behavior and expectation.

We are using the following formula to decide the number of questionnaire:

n=[z * se]2 Where n = sample size n=[1.96 * 50%5%]2 z= Confidence level =384 s= sample