voltages are equal, and ib −8 vg = = = −2 V 4 4 [b] To find the power associated with the 8 A source, we need to find the voltage drop across the source, vi . Note that the two independent sources are in parallel, and that the voltages vg and v1 have the same polarities, so these voltages are equal: vi = vg = −2 V Using the passive sign convention, ps = (8 A)(vi ) = (8 A)(−2 V) = −16 W Thus the current source generated 16 W of power. © 2010 Pearson Education, Inc., Upper Saddle River, NJ. All rights…
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