6302 homework 3 Problem 1: a) b) Resources | Task time | Capacity of resources | Markers | 1min | 5*1*60/1=300 | Adams | 2mins | 1*60/2=30 | Bob | 1min30secs | 1*3600/90=40 | Oven | 30secs | 6*1*3600/30=720 | rack | 3min15secs | 30*1*3600/195=553.84 | Chloe | 1min | 1*60/1=60 | fountain | 30secs | 1*3600/30=120 | Bottleneck=Adams=30 orders per hours Process capacity=30 orders per hours Demand rate=40 orders per hours Flow rate=30 orders per hours cycle time=1/flow rate= 2mins c) Rush order flow time=1+1.75+0.25+1.5+0.5+1=6mins Labor content of the process= 2+1.5+1=4.5 min=4min 30secs
d)
Costumers | Start time(sec) | End time(sec) | Adam begin his…show more content… Therefore, it will not increase revenue. g) Bottleneck=Adams=30 orders per hours Process capacity=30 orders per hours Demand rate=24orders per hours Flow rate=24 orders per hours cycle time=1/flow rate= 2.5mins When demand rate become 24 orders per hours in scenario i), ii), iii), all the flow rate will become 24 order per hours. All the attempts the manager made will not change the demand rate, so the flow rate will remain 24 orders per hours. Therefore, revenue will not increase in scenario i), ii), iii). In scenario vi), advertising will increase the demand rate, so it is possible to increase the flow rate, therefore increase the revenue.
h) Resources | Task time | Capacity of resources | Idle time | utilization | Markers | 1min | 5*1*60/1=300 | | | Adams | 2mins | 1*60/2=30 | 2-2=0min | 100% | Bob & Beatrix | 1min30secs | 2*1*3600/90=80 | 2*2-1.5=2.5min | 37.5% | Oven | 30secs | 6*1*3600/30=720 | | | rack | 3min15secs | 30*1*3600/195=553.84 | | | Chloe | 1min | 1*60/1=60 | 2-1=1min | 50% | fountain | 30secs | 1*3600/30=120 | | | Bottleneck=Adams=30 orders per hours Process capacity=30 orders per hours Demand rate=40 orders per hours Flow rate=30 orders per hours cycle time=1/flow rate= 2mins Average labor utilization= (100%+37.5%+37.5%+50%)/4*100%=56.25% Cost of direct
