AP 2.1 [a] Note that the current ib is in the same circuit branch as the 8 A current source; however, ib is defined in the opposite direction of the current source. Therefore, ib = −8 A Next, note that the dependent voltage source and the independent voltage source are in parallel with the same polarity. Therefore, their voltages are equal, and ib −8 vg = = = −2 V 4 4 [b] To find the power associated with the 8 A source, we need to find the voltage drop across the source, vi . Note that the two…
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