Stephanie Nihan
Michelle Murphy

PROBLEM 1
-5
0.066667
-4
0.063661
-3
0.061168
-2
0.059041
-1
0.057191
-0.1
0.055711
-0.01
0.055571

0.01
0.05554
0.1
0.055402
1
0.054093
2
0.052771
3
0.051567
4
0.050463
5
0.049444
LIMITS

A) If you try to evaluate the graph for f(0) there is an error and it says division by 0. This means it is undefined because you can’t divide by 0.
B) As x gets close to 0 the limit approaches 0.056.

*There is a curved line concaving down with a negative slope approaching 0.05.

*From the left it approaches 0.055

*From the right it approaches 0.055

*Yes because it approached 0.055 from both the left and the right sides of the graph.

*it appears to have a value at 0 but when tested there is a whole in the graph so the point at 0 is undefined.

1
-1
1.5
-3
1.9
-19
1.99
-199
2.01
201
2.1
21
2.5
5
3
3

A) It’s undefined because of division by 0
B) The graph approaches –infinity from the left and approaches +infinity from the right. Leaving an asymptote at x=2
* The graph starts at 1 and slowly curves until it gets close to 2 where it slowly approaches but never reaches 2 going to –infinity for y. From x=3 curves upwards towards infinity heading towards 2 but never hitting it.
* The left hand limit is negative infinity
* The right hand limit is positive infinity
* No the limit does not exist because the left and right hand limits are different
*The plot appears to have a value at x=2 but it doesn’t because there is an asymptote there

PROBLEM 3
1.3
4.9
1.4
5.2
1.48
5.44
1.49
5.47

1.51
5.53
1.52
5.56
1.53
5.59

Problem 3 Answers
A) When you evaluate f(3/2) you get 5.5
B) When you get close to 3/2 it approaches 5.5 but there is a hole in the graph
*A linear line with a positive slope and a hole at 1.5
*The left hand limit is 5.5
*The right hand limit is 5.5
*The limit exists because it approaches 5.5 from both sides.
*It has a hole in the graph because I picked numbers very close to the hole in the graph so it is a very zoomed in scale.
PROBLEM 4
-5
-1
-4
-1
-3
-1
-2
-1
-1
-1
-0.1
-1
-0.01
-1

0.01
1
0.1
1
1
1
2
1
3
1
4
1
5
1

Problem 4 Answers
A) f(0) is undefined because it is division by 0.
B) As x gets close to 0 it approaches -1 and 1 this is because of the absolute value sign in the numerator.
*The graph is 2 lines that come from –infinity and infinity but have a hole at 0.
*The left