Partner for Question 5 and 6 was Justin Ginges. a)
Hare
Time (minutes) | Distance (m) | 0-10 | 192 | 10-40 | 192 | 40-50 | 384 | 50-80 | 384 |
∴In 1 hour the hare travels 384m
Tortoise
Tortoise travels 5.4m per minute. There are 60 minutes in an hour.
∴Distance=5.4 ×60
=324
∴In 1 hour the tortoise travels 324m b) In 40mins hare travels 192m ×10=192m
In 40mins tortoise travels 5.4m ×40=216m
| Distance Travelled (m) | Time (Minutes) | Hare | Tortoise | 40 | 192 | 216 | 80 | 384 | 432 | 120 | 576 | 648 | 160 | 768 | 864 | 170 | 960 | 918 | 185.18518518 | 960 | 1000 | At 170 minutes, the Hare has just started his 30 minutes of sleeping and the tortoise has 82m of the race left.
Time it takes tortoise to travel 82m=82 ÷5.4
=15.185
The tortoise takes 15.185 minutes to complete the race after 918m, in this time the Hare is still sleeping.
1000-960=40
∴The Tortoise wins the race by 40 metres
c) If the tortoise maintained a hopping speed of 200m per minute, his pattern would be 200m of hopping the 30 minutes sleep. | Distance | Time (Minutes) | Hare | Tortoise | 40 | 200 | 216 | 80 | 400 | 432 | 120 | 600 | 648 | 160 | 800 | 864 | 170 | 1000 | 918 |
Looking at the table above, it can be seen that if the hare maintains a hopping speed of 20m per minute he can win the race and keep the same hopping pattern.